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Proof step 1008 from proof bitsand-cast (previous step)

# bits0 ≤ # bits1 ∧ bits0 ≠ [] ∧ ¬ bits0.first ⊦ bits1 = [], bits2 + bits1 = [], bits0 = [], bits1 = lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))), true ∈ bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1009:
# bits0 ≤ # bits1 ⊦ bits0 = [], bits1 = lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))), bits2 + bits1 = [], bits1 = [], bits0.first, true ∈ bits1

Proof step 1008 from proof bitsand-cast (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information