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Proof step 1014 from proof bitsand-cast (previous step)

¬(¬ true ∈ bits1 ∧ # bits0 < # bits1 ∧ ¬ bits0.first ∧ bits1 ≠ [] ∧ bits0 ≠ []), mklist(false, # bits1) = bits1, # bits0 ≤ # bits1 ⊦ bits0 = [], bits1 = lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))), bits2 + bits1 = [], bits1 = [], bits0.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1015:
mklist(false, # bits1) = bits1, # bits0 ≤ # bits1 ⊦ bits0 = [], bits1 = lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))), bits2 + bits1 = [], bits1 = [], bits0.first, ¬ true ∈ bits1 ∧ # bits0 ≠ # bits1

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ n → (n ≤ m ↔ m = n);% ⊦ ¬ m < n ↔ n ≤ m;