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Proof step 1016 from proof bitsand-cast (previous step)

¬ true ∈ bits1, mklist(false, # bits1) = bits1, # bits0 ≤ # bits1 ⊦ bits0 = [], bits1 = lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))), bits2 + bits1 = [], bits1 = [], bits0.first, ¬ true ∈ bits1 ∧ # bits0 ≠ # bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1017:
# bits0 = # bits1 ⊦ bits1 = [], bits2 + bits1 = [], bits1 = lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))), bits0 = [], true ∈ bits1, bits0.first

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ ¬ true ∈ bits → mklist(false, # bits) = bits;