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Proof step 120 from proof bitsand-cast (previous step)

¬(¬ false ∈ mklist(true, m) ∧ # bits2 ≤ # mklist(true, m) ∧ bits2.first ∧ bits2 ≠ []), # bits = 2 + # bits1, n = # fillsgn(n, mklist(true, m) + true ' + false ' + bits1), sgn(mklist(true, m) + true ' + false ' + bits1) = true ' + false ' + bits1, # bits2 < m, 2 + # bits1 + m < n ⊦ bits2 = [], bits = [], bits2 + bits = [], lastn(n, fillsgn(n, bits2 + bitsand(bits, true ' + false ' + bits1))) = lastn(n, fillsgn(n, bitsand(mklist(true, m), bits2) + bitsand(bits, true ' + false ' + bits1)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 121:
# bits = 2 + # bits1, n = # fillsgn(n, mklist(true, m) + true ' + false ' + bits1), sgn(mklist(true, m) + true ' + false ' + bits1) = true ' + false ' + bits1, # bits2 < m, 2 + # bits1 + m < n ⊦ bits2 = [], bits = [], bits2 + bits = [], lastn(n, fillsgn(n, bits2 + bitsand(bits, true ' + false ' + bits1))) = lastn(n, fillsgn(n, bitsand(mklist(true, m), bits2) + bitsand(bits, true ' + false ' + bits1))), bits2.first

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ # mklist(boolvar, n) = n;% ⊦ ¬ false ∈ mklist(true, n);