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Proof step 317 from proof bitsand-cast (previous step)

0 < n, n = # fillsgn(n, bits), # bits < n ⊦ bits = [], bits0 = [], lastn(n, mklist(false, n)) = lastn(n, fillsgn(n, bitsand(bits, bits0))), true ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 318:
n = # fillsgn(n, bits), # bits < n ⊦ bits = [], bits0 = [], mklist(false, n) = lastn(n, fillsgn(n, bitsand(bits, bits0))), true ∈ bits

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ 0 < n ↔ n ≠ 0;% ⊦ lastn(n, mklist(boolvar, n)) = mklist(boolvar, n);