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Proof step 320 from proof bitsand-cast (previous step)

¬(¬ true ∈ bits ∧ # bits0 < # bits ∧ ¬ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ []), n = # fillsgn(n, bits), # bits < n ⊦ bits = [], bits0 = [], mklist(false, n) = lastn(n, fillsgn(n, bitsand(bits, bits0))), true ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 321:
n = # fillsgn(n, bits), # bits < n ⊦ bits = [], bits0 = [], mklist(false, n) = lastn(n, fillsgn(n, bitsand(bits, bits0))), true ∈ bits, ¬ # bits ≤ # bits0 ∧ ¬ bits0.first

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;