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Proof step 323 from proof bitsand-cast (previous step)

¬ true ∈ bits ∧ (# bits ≤ # bits0 ∨ bits0.first) ∧ bits ≠ [] ∧ bits0 ≠ [], n = # fillsgn(n, bits), # bits < n ⊦ bits = [], bits0 = [], mklist(false, n) = lastn(n, fillsgn(n, bits)), true ∈ bits, ¬ # bits ≤ # bits0 ∧ ¬ bits0.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 324:
n = # fillsgn(n, bits), # bits < n, # bits ≤ # bits0 ∨ bits0.first ⊦ bits0 = [], bits = [], mklist(false, n) = fillsgn(n, bits), true ∈ bits, ¬ # bits ≤ # bits0 ∧ ¬ bits0.first

Rule argument

Additional information

Used simplifier rules: ⊦ n = # bits → lastn(n, bits) = bits;