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Proof step 347 from proof bitsand-cast (previous step)

¬ true ∈ bits ∧ # bits0 < # bits ∧ ¬ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ [], n = # fillsgn(n, bits), # bits < n ⊦ bits = [], bits0 = [], mklist(false, n) = lastn(n, fillsgn(n, mklist(false, # bits0))), true ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 348:
n = # fillsgn(n, bits), # bits0 + 1 < n, # bits0 < # bits, # bits < n, # bits0 < n ⊦ mklist(false, n) = lastn(n, fillsgn(n, mklist(false, # bits0))), bits0 = [], bits = [], bits0.first, true ∈ bits

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ∧ n = n0 → m < n0; (forward)% ⊦ m +1 = m + 1;% ⊦ # bits = 0 ↔ bits = [];% ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward)% ⊦ m < n → n ≠ 0; (forward)% ⊦ n < n0 ∧ n0 < n1 → n +1 < n1; (forward)