[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 360 from proof bitsand-cast (previous step)

n ≤ # bits ⊦ bits = [], bits0 = [], lastn(n, fillsgn(n, bitsand(sgn(lastn(n, bits)), bits0))) = lastn(n, fillsgn(n, bitsand(bits, bits0)))

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 361:
n ≤ # bits ⊦ ∃ bits0, bits1. bits = bits0 + bits1 ∧ # bits1 = n
Proof step 362:
∃ bits0, bits1. bits = bits0 + bits1 ∧ # bits1 = n, n ≤ # bits ⊦ bits = [], bits0 = [], lastn(n, fillsgn(n, bitsand(sgn(lastn(n, bits)), bits0))) = lastn(n, fillsgn(n, bitsand(bits, bits0)))

Rule argument

seq: n ≤ # bits ⊦ ∃ bits0, bits1. bits = bits0 + bits1 ∧ # bits1 = n subst: [n, bits] → [n, bits] rotate: F spec: list inst: bitlista name: split-rest

Additional information

Used terms: n, bits