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Proof step 384 from proof bitsand-cast (previous step)

sgn(mklist(boolvar, n - 1) + boolvar ' + boolvar0 ' + bits) = boolvar ' + boolvar0 ' + bits ⊦ ¬ 2 + # bits < # bits0, boolvar ↔ boolvar0, bits0 = [], n = 0, lastn(n + 1 + # bits, fillsgn(n + 1 + # bits, bitsand(boolvar ' + boolvar0 ' + bits, bits0))) = lastn(n + 1 + # bits, fillsgn(n + 1 + # bits, bitsand((bits2 + mklist(boolvar, n - 1)) + boolvar ' + boolvar0 ' + bits, bits0))), boolvar ∧ boolvar0, ¬ 2 + # bits < # bits0 ∧ ¬ bits0.first, ¬ 2 + # bits < # bits0 ∧ bits0.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 385:
sgn(mklist(boolvar, n - 1) + boolvar ' + boolvar0 ' + bits) = boolvar ' + boolvar0 ' + bits, 2 + # bits < # bits0 ⊦ lastn(n + 1 + # bits, fillsgn(n + 1 + # bits, bitsand(boolvar ' + boolvar0 ' + bits, bits0))) = lastn(n + 1 + # bits, fillsgn(n + 1 + # bits, bitsand((bits2 + mklist(boolvar, n - 1)) + boolvar ' + boolvar0 ' + bits, bits0))), n = 0, bits0 = [], boolvar ↔ boolvar0, boolvar ∧ boolvar0

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ m + n = n + m;