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Proof step 4 from proof bitsand-cast (previous step)

¬ n ≤ # bits ⊦ bits = [], bits0 = [], lastn(n, fillsgn(n, bitsand(sgn(lastn(n, fillsgn(n, bits))), bits0))) = lastn(n, fillsgn(n, bitsand(bits, bits0)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# bits < n ⊦ lastn(n, fillsgn(n, bitsand(sgn(lastn(n, fillsgn(n, bits))), bits0))) = lastn(n, fillsgn(n, bitsand(bits, bits0))), bits0 = [], bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;