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Proof step 460 from proof bitsand-cast (previous step)

¬ n0 ≤ n, 2 + # bits + n = n0 + # bits1, sgn((mklist(true, n) + mklist(true, # bits3)) + true ' + false ' + bits) = true ' + false ' + bits, # bits1 = 2 + # bits, bits3.first ⊦ mklist(true, n0) = lastn(n0, mklist(true, n)), bits3 + bitsand(bits1, true ' + false ' + bits) = [], bits2 + mklist(true, n) + mklist(true, # bits3) = [], bits3 = [], bits3 + bits1 = [], bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 461:
# bits1 = 2 + # bits, sgn((mklist(true, n) + mklist(true, # bits3)) + true ' + false ' + bits) = true ' + false ' + bits, 2 + # bits + n = n0 + # bits1, n < n0, bits3.first ⊦ bits1 = [], bits3 + bits1 = [], bits3 = [], bits2 + mklist(true, n) + mklist(true, # bits3) = [], bits3 + bitsand(bits1, true ' + false ' + bits) = [], mklist(true, n0) = lastn(n0, mklist(true, n))

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ ¬ m ≤ n ↔ n < m;