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Proof step 494 from proof bitsand-cast (previous step)

¬ # bits1 ≤ #(bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits)), # bits1 = 2 + # bits ⊦ bits4 = [], bits2 = [], lastn(# bits1, fillsgn(# bits1, bits4 + bitsand(bits1, true ' + false ' + bits))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits))), bits1 = [], bits4 + bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 495:
# bits1 = 2 + # bits, # bitsand(bits2, bits4) + # bitsand(bits1, true ' + false ' + bits) < # bits1 ⊦ bits4 + bits1 = [], bits1 = [], lastn(# bits1, fillsgn(# bits1, bits4 + bitsand(bits1, true ' + false ' + bits))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits))), bits2 = [], bits4 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ m < n ∧ n = n0 → m < n0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ #(bits + bits0) = # bits + # bits0;