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Proof step 497 from proof bitsand-cast (previous step)

# bits1 ≤ #(bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits)), # bits1 = 2 + # bits ⊦ bits4 = [], bits2 = [], lastn(# bits1, fillsgn(# bits1, bits4 + bitsand(bits1, true ' + false ' + bits))) = lastn(# bits1, bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits)), bits1 = [], bits4 + bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 498:
# bits1 = 2 + # bits, # bits1 ≤ # bitsand(bits2, bits4) + # bitsand(bits1, true ' + false ' + bits) ⊦ bits4 = [], bits2 = [], lastn(# bits1, fillsgn(# bits1, bits4 + bitsand(bits1, true ' + false ' + bits))) = lastn(# bits1, bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits)), bits1 = [], bits4 + bits1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ #(bits + bits0) = # bits + # bits0;