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Proof step 500 from proof bitsand-cast (previous step)

(true ' + false ' + bits).first ∧ #(true ' + false ' + bits) ≤ # bits1 ∧ true ' + false ' + bits ≠ [], # bits1 = 2 + # bits, # bits1 ≤ # bitsand(bits2, bits4) + # bits1 ⊦ bits4 = [], bits2 = [], lastn(# bits1, fillsgn(# bits1, bits4 + bitsand(bits1, true ' + false ' + bits))) = lastn(# bits1, bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits)), bits1 = [], bits4 + bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 501:
# bits1 = 2 + # bits ⊦ bits4 + bits1 = [], bits1 = [], lastn(# bits1, fillsgn(# bits1, bits4 + bitsand(bits1, true ' + false ' + bits))) = lastn(# bits1, bitsand(bits2, bits4) + bitsand(bits1, true ' + false ' + bits)), bits2 = [], bits4 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m ≤ m + n;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (boolvar ' + bits).first ↔ boolvar;% ⊦ boolvar ' + bits ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;