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Proof step 648 from proof bitsand-cast (previous step)

2 + # bits + m ≤ #(mklist(false, m) + bitsand(false ' + true ' + bits, bits1)), # bits1 = 2 + # bits, # bits1 ≤ # bits2 + # bitsand(false ' + true ' + bits, bits1), # bits3 ≤ m, bits3.first ⊦ m = 0, bits3 = [], mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = lastn(2 + # bits + m, mklist(false, m) + bitsand(false ' + true ' + bits, bits1)), bits1 = [], bits2 + mklist(false, m) = [], bits3 + bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 649:
# bits1 = 2 + # bits, # bits1 ≤ # bits2 + # bitsand(false ' + true ' + bits, bits1), # bits3 ≤ m, bits3.first, # bits1 ≤ # bitsand(false ' + true ' + bits, bits1) ⊦ m = 0, bits3 = [], mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = lastn(2 + # bits + m, mklist(false, m) + bitsand(false ' + true ' + bits, bits1)), bits1 = [], bits2 + mklist(false, m) = [], bits3 + bits1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n ≤ m + n0 ↔ n ≤ n0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # mklist(boolvar, n) = n;% ⊦ #(bits + bits0) = # bits + # bits0;