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Proof step 657 from proof bitsand-cast (previous step)

2 + # bits + m = #(mklist(false, m) + bitsand(false ' + true ' + bits, bits1)), # bits1 = 2 + # bits, # bits1 ≤ # bits2 + # bitsand(false ' + true ' + bits, bits1), # bits3 ≤ m, bits3.first, # bits1 ≤ # bitsand(false ' + true ' + bits, bits1) ⊦ m = 0, bits3 = [], mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = mklist(false, m) + bitsand(false ' + true ' + bits, bits1), bits1 = [], bits2 + mklist(false, m) = [], bits3 + bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 658:
# bits1 = # bitsand(false ' + true ' + bits, bits1), # bits1 = 2 + # bits, bits3.first, # bits3 ≤ m ⊦ bitsand(bits1, false ' + true ' + bits) = bitsand(false ' + true ' + bits, bits1), bits3 = [], m = 0, bits3 + bits1 = [], bits2 + mklist(false, m) = [], bits1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ m ≤ m + n;% ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward)% ⊦ bits + bits0 = bits + bits1 ↔ bits0 = bits1;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = m + n0 ↔ n = n0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # mklist(boolvar, n) = n;% ⊦ #(bits + bits0) = # bits + # bits0;