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Proof step 685 from proof bitsand-cast (previous step)

# bits1 = 2 + # bits, 2 + # bits + m < # bits3 + # bitsand(bits1, false ' + true ' + bits), # bits3 < m ⊦ bits1 = [], bits3 = [], bits3 + bits1 = [], bits2 + mklist(false, m) = [], mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = lastn(2 + # bits + m, fillsgn(2 + # bits + m, mklist(false, # bits3) + bitsand(bits1, false ' + true ' + bits))), # bits3 = m, 2 + # bits + m = # fillsgn(2 + # bits + m, mklist(false, # bits3) + bitsand(bits1, false ' + true ' + bits)), bits3.first

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: bitsand-len-false rotate: F subst: [bits0, bits] → [false ' + true ' + bits, bits1]

Additional information

Used simplifier rules: ⊦ m + n < m + n0 ↔ n < n0;% ⊦ boolvar ' + bits ≠ [];% ⊦ (boolvar ' + bits).first ↔ boolvar;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ # boolvar ' = 0 +1;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ boolvar ' ≠ [];% ⊦ m < n ∧ m = n0 → n0 < n; (forward)% ⊦ m < n ∧ n = n0 → m < n0; (forward)% ⊦ m < n → n ≠ 0; (forward)% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → ¬ n < m; Used terms: false ' + true ' + bits, bits1