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Proof step 761 from proof bitsand-cast (previous step)

¬ (false ' + true ' + bits).first ∧ #(false ' + true ' + bits) ≤ # bits1 ∧ false ' + true ' + bits ≠ [], # bits1 = #(false ' + true ' + bits), 2 + # bits = # bits1, # bitsand(false ' + true ' + bits, bits1) < # bits1, # bits1 ≤ # bitsand(bits2, bits4) + # bitsand(false ' + true ' + bits, bits1) ⊦ bitsand(bits1, false ' + true ' + bits) = lastn(# bits1, bitsand(bits2, bits4) + bitsand(false ' + true ' + bits, bits1)), bits1 = [], bits2 = [], bits4 = [], bits4 + bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 762:
# bits1 = 2 + # bits, # bits1 ≤ # bitsand(bits2, bits4) + # bitsand(false ' + true ' + bits, bits1), # bitsand(false ' + true ' + bits, bits1) < # bits1 ⊦ bits4 + bits1 = [], bits4 = [], bits2 = [], bits1 = [], bitsand(bits1, false ' + true ' + bits) = lastn(# bits1, bitsand(bits2, bits4) + bitsand(false ' + true ' + bits, bits1))

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ m < n ∧ n ≤ n0 → m < n0; (forward)% ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward)% ⊦ (boolvar ' + bits).first ↔ boolvar;% ⊦ boolvar ' + bits ≠ [];% ⊦ m + n = n + m;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;