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Proof step 775 from proof bitsand-cast (previous step)

¬ (false ' + true ' + bits).first ∧ #(false ' + true ' + bits) ≤ # bits1 ∧ false ' + true ' + bits ≠ [], # bits1 = 2 + # bits, # bits1 ≤ # bitsand(bits2, bits4) + #(false ' + true ' + bits), # bits1 ≤ #(false ' + true ' + bits) ⊦ bitsand(bits1, false ' + true ' + bits) = lastn(# bits1, bitsand(bits1, false ' + true ' + bits)), bits2 = [], bits4 = [], bits4 + bits1 = [], bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 776:
# bits1 = 2 + # bits ⊦ bits1 = [], bits4 + bits1 = [], bits4 = [], bits2 = [], bitsand(bits1, false ' + true ' + bits) = lastn(# bits1, bitsand(bits1, false ' + true ' + bits))

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m ≤ m + n;% ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward)% ⊦ (boolvar ' + bits).first ↔ boolvar;% ⊦ m ≤ n → (n ≤ m ↔ m = n);% ⊦ m + n = n + m;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ boolvar ' + bits ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;