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Proof step 866 from proof bitsand-cast (previous step)

true ∈ bits1 ⊦ bits2 + bits1 = [], bits0 = [], lastn(# bits1, fillsgn(# bits1, bitsand(sgn(bits1), bits0))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2 + bits1, bits0))), false ∈ bits1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 867:
⊦ ¬ boolvar ∈ bits ↔ mklist(¬ boolvar, # bits) = bits
Proof step 868:
true ∈ bits1 ⊦ bits2 + bits1 = [], bits0 = [], lastn(# bits1, fillsgn(# bits1, bitsand(sgn(bits1), bits0))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2 + bits1, bits0))), mklist(¬ false, # bits1) ≠ bits1

Rule argument

seq: ⊦ ¬ boolvar ∈ bits ↔ mklist(¬ boolvar, # bits) = bits subst: [bits, boolvar] → [bits1, false] rotate: F spec: bitlista inst: name: mklist-intro

Additional information

Used terms: bits1, false