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Proof step 897 from proof bitsand-cast (previous step)

# bits1 ≤ #(mklist(true, n) + bits0), # bits1 = n + # bits0, bits0.first, # bits0 < # bits1, # bits0 < # bits2 + # bits1 ⊦ mklist(true, n) + bits0 = lastn(# bits1, mklist(true, n) + bits0), bits1 = [], bits2 + bits1 = [], bits0 = [], n = 0, false ∈ bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 898:
# bits1 = n + # bits0, # bits0 < # bits1, # bits0 < # bits2 + # bits1, bits0.first ⊦ n = 0, bits0 = [], bits2 + bits1 = [], bits1 = [], mklist(true, n) + bits0 = lastn(# bits1, mklist(true, n) + bits0), false ∈ bits1

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ m + n = n + m;% ⊦ m < n ∧ n ≤ n0 → m < n0; (forward)% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # mklist(boolvar, n) = n;% ⊦ #(bits + bits0) = # bits + # bits0;