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Proof step 907 from proof bitsand-cast (previous step)

∃ bits3, bits2. bits0 = bits3 + bits2 ∧ # bits2 = # bits1, # bits1 ≤ # bits0, mklist(true, # bits1) = bits1 ⊦ bits2 + bits1 = [], bits0 = [], lastn(# bits1, bits0) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2 + bits1, bits0))), bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 908:
mklist(true, # bits1) = bits1, # bits = # bits1 ⊦ bits = lastn(# bits1, fillsgn(# bits1, bitsand(bits2 + bits1, bits3 + bits))), bits3 + bits = [], bits2 + bits1 = [], bits1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m ≤ m + n;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ n = # bits → lastn(n, bits0 + bits) = bits;