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Proof step 952 from proof bitsand-cast (previous step)

¬ false ∈ bits1 ∧ # bits1 ≤ # bits ∧ bits1 ≠ [], # bits = # bits1, mklist(true, # bits1) = bits1 ⊦ bits2 = [], bits3 = [], bits1 = [], bits2 + bits1 = [], bits3 + bits = [], bits = lastn(# bits1, fillsgn(# bits1, bitsand(bits2, bits3) + bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 953:
# bits = # bits1 ⊦ bits1 = [], bits = lastn(# bits1, fillsgn(# bits1, bitsand(bits2, bits3) + bits)), bits3 + bits = [], bits2 + bits1 = [], bits3 = [], bits2 = [], false ∈ bits1

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ ¬ false ∈ bits → mklist(true, # bits) = bits;