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Proof step 990 from proof bitsand-cast (previous step)

# bits1 ≤ #(bitsand(bits2, bits3) + bits1), # bits = # bits1 ⊦ bits1 = [], bits = [], bits1 = lastn(# bits1, bitsand(bits2, bits3) + bits1), bits3 + bits = [], bits2 + bits1 = [], bits3 = [], bits2 = [], true ∈ bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 991:
# bits = # bits1 ⊦ bits1 = [], bits = [], bits1 = lastn(# bits1, bitsand(bits2, bits3) + bits1), bits3 + bits = [], bits2 + bits1 = [], bits3 = [], bits2 = [], true ∈ bits1

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m ≤ m + n;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ #(bits + bits0) = # bits + # bits0;