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Proof step 58 from proof bitsand-fillsgn (previous step)

∀ n, bits, bits1. # bits1 < #(false + []) → true → bits = [] ∨ bits1 = [] ∨ fillsgn(n, bitsand(fillsgn(n, bits), bits1)) = fillsgn(n, bitsand(bits, bits1)) ⊦ n0 = 1, n0 = 0, fillsgn(n0, false ') = mklist(false, n0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 59:
⊦ 0 < n → fillsgn(n, boolvar ') = mklist(boolvar, n)

Rule argument

seq: ⊦ 0 < n → fillsgn(n, boolvar ') = mklist(boolvar, n) subst: [boolvar, n] → [false, n0] rotate: F spec: bitopsaux inst: name: fill-rec-one

Additional information

Used simplifier rules: ⊦ 0 < n ↔ n ≠ 0; Used terms: false, n0