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Proof step 27 from proof bitsand-first-samesize (previous step)

# bits2 + 1 = # bits, ∀ boolvar0, boolvar, bits1, bits0. # bits0 < # bits → # bits1 = # bits0 → bits0 = [] ∨ bitsand(boolvar ' + bits1, boolvar0 ' + bits0) = (boolvar ∧ boolvar0)' + bitsand(bits1, bits0) ⊦ # bits = 1, bitsand(boolvar ' + bits2 + boolvar1 ', boolvar0 ' + bits) = (boolvar ∧ boolvar0)' + bitsand(bits2, bits.butlast) + (boolvar1 ∧ bits.last)', bits = []

User applied rule insert elim lemma

And obtained the following new goals

Proof step 28:
bits = bits3 + boolvar2 ', # bits2 + 1 = # bits, ∀ boolvar0, boolvar, bits1, bits0. # bits0 < # bits → # bits1 = # bits0 → bits0 = [] ∨ bitsand(boolvar ' + bits1, boolvar0 ' + bits0) = (boolvar ∧ boolvar0)' + bitsand(bits1, bits0) ⊦ # bits = 1, bitsand(boolvar ' + bits2 + boolvar1 ', boolvar0 ' + bits) = (boolvar ∧ boolvar0)' + bitsand(bits2, bits3) + (boolvar1 ∧ boolvar2)', bits = []

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar ' subst: [bits, boolvar, bits0] → [bits, boolvar2, bits3] rotate: T spec: list-last inst: bitlista name: last-elim

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar '; (elim) Used terms: bits, boolvar2, bits3