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Proof step 5 from proof bitsand-first-samesize (previous step)

bits0 = boolvar0 + bits ∧ bits0 ≠ [], 1 + # bits1 = # bits0 ⊦ # bits0 = 1, bitsand(boolvar ' + bits1, bits0) = (boolvar ∧ boolvar0)' + bitsand(bits1, bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
# bits1 = # bits ⊦ bits = [], bitsand(boolvar ' + bits1, boolvar0 ' + bits) = (boolvar ∧ boolvar0)' + bitsand(bits1, bits)

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ' + bits ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = m + n0 ↔ n = n0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ boolvar + bits = boolvar ' + bits;