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Proof step 10 from proof bitsand-idempotent (previous step)

∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ bitsand(bits0, bits0) = bits0 ⊦ bits = [], bitsand(bits.butlast, bits.butlast) + bits.last ' = bits, # bits = 1

User applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
bits = bits1 + boolvar ', ∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ bitsand(bits0, bits0) = bits0 ⊦ bits = [], bitsand(bits1, bits1) + boolvar ' = bits, # bits = 1

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar ' subst: [bits, boolvar, bits0] → [bits, boolvar, bits1] rotate: T spec: list-last inst: bitlista name: last-elim

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar '; (elim) Used terms: bits, boolvar, bits1