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Proof step 7 from proof bitsand-idempotent (previous step)

# bits = 1, ∀ bits0. # bits0 < 1 → true → bits0 = [] ∨ bitsand(bits0, bits0) = bits0 ⊦ bitsand(bits, bits) = bits, bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ bits ≠ [] ∧ bits0 = true ' → bitsand(bits, bits0) = bits

Rule argument

name: and-rec-01 rotate: F subst: [bits0, bits] → [bits, bits]

Additional information

Used simplifier rules: and-one: ⊦ bitsand(boolvar ', boolvar0 ') = (boolvar ∧ boolvar0)';% ⊦ # bits = 1 ∧ bits ≠ true ' → bits = false '; (forward)% ⊦ # boolvar ' = 0 +1;% ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ boolvar ' ≠ []; Used terms: bits, bits