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Proof step 13 from proof bitsand-len-false (previous step)

# bits3 < # bits2, ∀ bits, bits0. # bits0 < #(bits3 + boolvar ') → # bits0 < # bits → # bitsand(bits, false ' + bits0) = 1 + # bits0 ∨ bits = [] ⊦ # bitsand(bits2, false ' + bits3) = # bits3 + 1, bits2 = []

User applied rule apply induction

And closed the goal!

Rule argument

subst: [bits, bits0] → [bits2, bits3]

Additional information

Used simplifier rules: ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ # boolvar ' = 0 +1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ m < n + 1 ↔ ¬ n < m;% ⊦ ¬ n < n;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: bits2, bits3