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Proof step 5 from proof bitsand-len-false (previous step)

# bits1 < # bits, ∀ bits, bits0. # bits0 < # bits1 → # bits0 < # bits → # bitsand(bits, false ' + bits0) = 1 + # bits0 ∨ bits = [] ⊦ # bitsand(bits, false ' + bits1) = 1 + # bits1 ∨ bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
# bits1 < # bits, ∀ bits, bits0. # bits0 < # bits1 → # bits0 < # bits → # bitsand(bits, false ' + bits0) = 1 + # bits0 ∨ bits = [] ⊦ bits = [], # bitsand(bits, false ' + bits1) = 1 + # bits1

Proof step 5 from proof bitsand-len-false (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information