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Proof step 24 from proof bitsand-onein (previous step)

∀ bits0, bits, bits2. # bits2 < # bits1 → true → bits2 = [] ∨ (true ∈ bitsand(bits + false ' + bits0, bits2) ↔ true ∈ bitsand(false ' + bits0, bits2)) ∨ true ∈ bits ⊦ bits1 = [], true ∈ bitsand(bits + false ' + bits3 + boolvar ', bits1) ↔ true ∈ bitsand(false ' + bits3, bits1.butlast) ∨ boolvar ∧ bits1.last, # bits1 = 1, true ∈ bits

User applied rule insert elim lemma

And obtained the following new goals

Proof step 25:
bits1 = bits4 + boolvar0 ', ∀ bits0, bits, bits2. # bits2 < # bits1 → true → bits2 = [] ∨ (true ∈ bitsand(bits + false ' + bits0, bits2) ↔ true ∈ bitsand(false ' + bits0, bits2)) ∨ true ∈ bits ⊦ bits1 = [], true ∈ bitsand(bits + false ' + bits3 + boolvar ', bits1) ↔ true ∈ bitsand(false ' + bits3, bits4) ∨ boolvar ∧ boolvar0, # bits1 = 1, true ∈ bits

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar ' subst: [bits, boolvar, bits0] → [bits1, boolvar0, bits4] rotate: T spec: list-last inst: bitlista name: last-elim

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar '; (elim) Used terms: bits1, boolvar0, bits4