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Proof step 1 from proof bitsand-zeros-01 (conclusion)

⊦ ¬ true ∈ bits ∧ (# bits0 < # bits ∧ ¬ bits0.first) ∧ bits ≠ [] ∧ bits0 ≠ [] → bitsand(bits, bits0) = mklist(false, # bits0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# bits0 < # bits ⊦ bits = [], bits0 = [], bitsand(bits, bits0) = mklist(false, # bits0), true ∈ bits, bits0.first

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)