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Proof step 2 from proof bitsand-zeros-02 (previous step)

⊦ bits = [], bits0 = [], sgn(bitsand(bits, bits0)) = false ', true ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ¬ true ∈ bits ∧ (# bits ≤ # bits0 ∨ bits0.first) ∧ bits ≠ [] ∧ bits0 ≠ [] → bitsand(bits, bits0) = bits
Proof step 4:
¬(¬ true ∈ bits ∧ (# bits ≤ # bits0 ∨ bits0.first) ∧ bits ≠ [] ∧ bits0 ≠ []) ⊦ bits = [], bits0 = [], sgn(bitsand(bits, bits0)) = false ', true ∈ bits

Rule argument

name: bitsand-zeros rotate: F subst: [bits0, bits] → [bits0, bits]

Additional information

Used simplifier rules: ⊦ ¬ true ∈ bits ∧ bits ≠ [] → sgn(bits) = false ';% ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0; Used terms: bits0, bits