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Proof step 6 from proof bitsand-zeros-02 (previous step)

bits0 = boolvar + bits1, # bits0 < # bits ⊦ sgn(bitsand(bits, bits0)) = false ', bits0 = [], bits = [], boolvar, true ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
1 + # bits1 < # bits ⊦ bits = [], sgn(bitsand(bits, false ' + bits1)) = false ', true ∈ bits

Rule argument

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;