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Proof step 18 from proof bitsor-app (previous step)

∀ bits1, bits, bits2, bits3. # bits3 < #([] + boolvar ') → true → # bits3 = # bits2 ∧ bits ≠ [] ∧ bits3 ≠ [] ∧ bits1 ≠ [] ∧ bits2 ≠ [] → bitsor(bits + bits3, bits1 + bits2) = bitsor(bits, bits1) + bitsor(bits3, bits2) ⊦ bits = [], bits1 = [], boolvar ' = bitsor(boolvar ', false ')

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ bits ≠ [] ∧ bits0 = false ' → bitsor(bits, bits0) = bits

Rule argument

name: or-rec-02 rotate: F subst: [bits0, bits] → [false ', boolvar ']

Additional information

Used simplifier rules: ⊦ boolvar ' ≠ []; Used terms: false ', boolvar '