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Proof step 51 from proof bitsor-bi-sgn (previous step)

∀ bits, bits1. # bits1 < #(bits3 + boolvar0 ') → true → bits ≠ [] ∧ bits1 ≠ [] → bits2int(bitsor(sgn(bits), bits1)) = bits2int(bitsor(bits, bits1)) ⊦ ~1 = bits2int(true ' + true '), bits3 = [], false ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 52:
⊦ ¬ false ∈ bits ∧ bits ≠ [] → bits2int(bits) = ~1

Rule argument

seq: ⊦ ¬ false ∈ bits ∧ bits ≠ [] → bits2int(bits) = ~1 subst: [bits] → [true ' + true '] rotate: F spec: int2bits inst: name: bits2int-ones

Additional information

Used simplifier rules: ⊦ boolvar ∈ bits + bits0 ↔ ¬ ¬(boolvar ∈ bits ∨ boolvar ∈ bits0);% ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ boolvar ' ≠ []; Used terms: true ' + true '