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Proof step 60 from proof bitsor-bi-sgn (previous step)

∀ bits, bits1. # bits1 < #(bits3 + boolvar0 ') → true → bits ≠ [] ∧ bits1 ≠ [] → bits2int(bitsor(sgn(bits), bits1)) = bits2int(bitsor(bits, bits1)) ⊦ bits2int(bitsor(false ', bits3) + true ') = bits2int(bitsor(false ' + bits0, bits3) + true '), bits3 = [], true ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 61:
⊦ bits0 ≠ [] ∧ bits = false ' → bitsor(bits, bits0) = bits0
Proof step 62:
bits3 ≠ [] ∧ false ' = false ', ∀ bits, bits1. # bits1 < #(bits3 + boolvar0 ') → true → bits ≠ [] ∧ bits1 ≠ [] → bits2int(bitsor(sgn(bits), bits1)) = bits2int(bitsor(bits, bits1)) ⊦ bits2int(bits3 + true ') = bits2int(bitsor(false ' + bits0, bits3) + true '), bits3 = [], true ∈ bits0

Rule argument

name: or-rec-04 rotate: F subst: [bits0, bits] → [bits3, false ']

Additional information

Used terms: bits3, false '