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Proof step 31 from proof bitsor-bi-zeroes (previous step)

# bits0 = # bits2 ⊦ bits3 + bits0 = [], bits2int((bitsor(bits3, false ') + bitsor(bits0, bits2)) + bits1) = bits2uint(bits2 + bits1), # bits3 = 1, bits2 = [], bits0 = [], bits3 = [], true ∈ bits3, true ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 32:
⊦ bits ≠ [] ∧ bits0 = false ' → bitsor(bits, bits0) = bits
Proof step 33:
bits3 ≠ [] ∧ false ' = false ', # bits0 = # bits2 ⊦ bits3 + bits0 = [], bits2int((bits3 + bitsor(bits0, bits2)) + bits1) = bits2uint(bits2 + bits1), # bits3 = 1, bits2 = [], bits0 = [], bits3 = [], true ∈ bits3, true ∈ bits0

Rule argument

name: or-rec-02 rotate: F subst: [bits0, bits] → [false ', bits3]

Additional information

Used terms: false ', bits3