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Proof step 4 from proof bitsor-bi-zeroes (previous step)

¬(¬ true ∈ bits ∧ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ []) ⊦ bits = [], bits0 = [], bits2int(bitsor(bits, bits0) + bits1) = bits2int(bits0 + bits1), true ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ bits = [], bits0 = [], bits2int(bitsor(bits, bits0) + bits1) = bits2int(bits0 + bits1), true ∈ bits, bits0.first

Proof step 4 from proof bitsor-bi-zeroes (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information