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Proof step 43 from proof bitsor-bi-zeroes (previous step)

¬ true ∈ bits, # bits0 = # bits2 ⊦ bits2 = [], bits0 = [], bits2uint(bitsor(bits0, bits2) + bits1) = bits2uint(bits2 + bits1), bits = [], true ∈ bits0, true ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 44:
# bits0 = # bits2 ⊦ bits = [], bits2uint(bitsor(bits0, bits2) + bits1) = bits2uint(bits2 + bits1), bits0 = [], bits2 = [], true ∈ bits, true ∈ bits0

Proof step 43 from proof bitsor-bi-zeroes (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information