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Proof step 6 from proof bitsor-bi-zeroes (previous step)

bits0 = boolvar + bits2 ⊦ bits = [], bits0 = [], bits2int(bitsor(bits, bits0) + bits1) = bits2int(bits0 + bits1), true ∈ bits, boolvar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ bits = [], bits2int(bitsor(bits, false ' + bits2) + bits1) = bits2uint(bits2 + bits1), true ∈ bits

Rule argument

Additional information

Used simplifier rules: ⊦ bits2int(false ' + bits) = bits2uint(bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;