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Proof step 14 from proof bitsor-com (previous step)

¬(bits0 ≠ [] ∧ bits = true '), # bits = 1, ∀ bits, bits1. # bits1 < # bits0 → true → bits ≠ [] ∧ bits1 ≠ [] → bitsor(bits, bits1) = bitsor(bits1, bits) ⊦ bits = [], bits0 = [], bitsor(bits, bits0) = bitsor(bits0, bits), bits0 = true ', bits0 = false ', # bits0 = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
∀ bits, bits1. # bits1 < # bits0 → true → bits ≠ [] ∧ bits1 ≠ [] → bitsor(bits, bits1) = bitsor(bits1, bits) ⊦ # bits0 = 1, bits0 = false ', bits0 = true ', bitsor(false ', bits0) = bitsor(bits0, false '), bits0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ' ≠ [];% ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ # boolvar ' = 0 +1;% ⊦ # bits = 1 ∧ bits ≠ true ' → bits = false '; (forward)