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Proof step 17 from proof bitsor-com (previous step)

bits0 ≠ [] ∧ false ' = false ', ∀ bits, bits1. # bits1 < # bits0 → true → bits ≠ [] ∧ bits1 ≠ [] → bitsor(bits, bits1) = bitsor(bits1, bits) ⊦ # bits0 = 1, bits0 = false ', bits0 = true ', bits0 = bitsor(bits0, false '), bits0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
∀ bits, bits1. # bits1 < # bits0 → true → bits ≠ [] ∧ bits1 ≠ [] → bitsor(bits, bits1) = bitsor(bits1, bits) ⊦ # bits0 = 1, bits0 = false ', bits0 = true ', bits0 = bitsor(bits0, false '), bits0 = []

Proof step 17 from proof bitsor-com (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information