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Proof step 21 from proof bitsor-com (previous step)

∀ bits, bits1. # bits1 < # bits0 → true → bits ≠ [] ∧ bits1 ≠ [] → bitsor(bits, bits1) = bitsor(bits1, bits) ⊦ true ' = bitsor(bits0, true '), bits0 = true ', bits0 = false ', # bits0 = 1, bits0 = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ bits ≠ [] ∧ bits0 = true ' → bitsor(bits, bits0) = true '

Rule argument

name: or-rec-01 rotate: F subst: [bits0, bits] → [true ', bits0]

Additional information

Used terms: true ', bits0