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Proof step 3 from proof bitsor-first-01 (previous step)

bits = boolvar + bits1 ⊦ bits = [], bits0 = [], bitsor(bits, bits0).first ↔ boolvar ∨ bits0.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ bits0 = [], bitsor(boolvar ' + bits1, bits0).first ↔ boolvar ∨ bits0.first

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;