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Proof step 7 from proof bitsor-first-01 (previous step)

⊦ bitsor(boolvar ' + bits1, boolvar0 ' + bits) ≠ [], bitsor(boolvar ' + bits1, boolvar0 ' + bits).first ↔ boolvar ∨ boolvar0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information