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Proof step 1 from proof bitsor-first-02 (conclusion)

⊦ ¬ bits.first ∧ ¬ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ [] → bitsor(bits, bits0) ≠ true ' + bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bitsor(bits, bits0) = true ' + bits1, true ∈ bitsor(bits, bits0) ⊦ bits0 = [], bits = [], bits0.first, bits.first

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)