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Proof step 14 from proof bitsor-mklist-in (previous step)

mklist(boolvar0, n) + bits ≠ [] ∧ false ' = false ', ∀ bits, boolvar0, boolvar, n, bits1. # bits1 < 1 → true → n = 0 ∨ bits1 = [] ∨ (boolvar ∈ bitsor(mklist(boolvar0, n) + bits, bits1) ↔ boolvar ∈ bitsor(boolvar0 ' + bits, bits1)) ⊦ n = 0, boolvar ∈ mklist(boolvar0, n) + bits ↔ boolvar ∈ bitsor(boolvar0 ' + bits, false ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
∀ bits, boolvar0, boolvar, n, bits1. # bits1 < 1 → true → n = 0 ∨ bits1 = [] ∨ (boolvar ∈ bitsor(mklist(boolvar0, n) + bits, bits1) ↔ boolvar ∈ bitsor(boolvar0 ' + bits, bits1)) ⊦ mklist(boolvar0, n) + bits = [], n = 0, boolvar ∈ mklist(boolvar0, n) ∨ boolvar ∈ bits ↔ boolvar ∈ bitsor(boolvar0 ' + bits, false ')

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ∈ bits + bits0 ↔ ¬ ¬(boolvar ∈ bits ∨ boolvar ∈ bits0);